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2 SrO
+
2 F
2
→
2 SrF
2
+
O
2
SrO = reagent
A
F
2
= reagent
B
A
B
When 4.96 grams of SrO react with 7.36 grams of F
2
, which is the limiting reagent?
(For a look-up table of formula weights, click
here
.)
How many grams of the excess reagent remain?
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How many grams of O
2
are produced in the reaction?
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