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Re
2
S
7
+
H
2
→
2 ReS
3
+
H
2
S
H
2
= reagent
A
Re
2
S
7
= reagent
B
A
B
When 8.05 grams of H
2
react with 5.53 grams of Re
2
S
7
, which is the limiting reagent?
(For a look-up table of formula weights, click
here
.)
How many grams of the excess reagent remain?
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How many grams of ReS
3
are produced in the reaction?
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